The electron and antineutrino take energy to create, presumably taking away from the energy available for photon emission and constraining the energy of any emitted gamma rays, right? Or is the energy required to create them not at all related to the excitation energy levels of the nucleus? I'm...
So it's decay to the excited state is what allows for the emission of gamma rays (once relaxation occurs), at least that's what I gather. Like you said, the ##Q## value isn't really of use here, but it is higher than the second excited state of ##^{198}\text{Hg}##. What happens to this extra...
Can we just treat these as plain old photon emission transitions? i.e. ##E_{\gamma_1}=1.008 \, MeV - 0.412 \, MeV, \, E_{\gamma_2}=1.008 \, MeV - 0, \, E_{\gamma_3}=0.412 \, MeV - 0.##? If so than this question 1. is a lot easier than expected but also 2. leaves me even more confused as to what...
This is what I have for my solution thus far:
"For gold to transition to mercury, it must exchange one of it's neutrons for a proton via ##\beta##-decay. In order to find the energy of the emitted gamma rays, we must first find the excess rest energy ##Q## present after the ##\beta##-decay. The...
I am currently a junior (soon to be senior) undergraduate physics major and decided to join the physics forums because I have already gotten a good amount of help and understanding just by perusing past conversations without an account, and because I know that physics is not a subject easily...