Office_Shredder's latest activity

It's just a list of names of textbooks, technically by the way the request was worded

If you subtract ##A\cap C## from the left side of everything, and ##B\cap D## on the right side, then you have reduced to the case of no...

A and B are matrices you know, and ##\,omega## is a number that you know, so you can plug them all in and you get like like ##Cx=0## for...

Hint: ##\cos x \leq 1##.

I find it a bit weird to suggest someone compute the derivative of cos(x) as a substep in their struggle to compute the derivative of...

I think if a Hilbert space has a countable Schauder basis, then it has a countable Hilbert basis. You can basically just apply Grahm...

I was expressing ##\delta## as a function of ##\epsilon##. It is not true that ##\delta \leq \epsilon## in general

I don't really understand what the point of letting you use that inequality is (especially since you proved it in question 7, so it's...

I agree that this function is uniformly continuous, but you said it "must" be uniformly continuous and it's not true that continuous...

If e is a function from ##(-c(d),c(d))\to \mathbb{R}## then since the domain is an open interval the endpoints aren't in the domain...

The squeeze principle requires the smallest and largest things to become equal in the limit. 2/3 and 2 are not equal, no matter how...

You can use the chain rule to express the derivative of e in terms of the derivative of c. This lets you put bounds on the derivative of...

What you said sounds right to me

Yes

Yes, every Hilbert space has an orthogonal basis. I think you need to assume the axiom of choice for this to be true or something.