So I have to show 2sin^2(x) and -cos(2x) have the same antiderative.
Here's how I approached this.
2sin^2(x) = 1-cos2x ==> u = 2x
intergral of that is
(u - sinu)/2 + c = x - (sinx)/2 + c
-cos2x ==> u = 2x
intregal of that is
(-sinu)/2 + c= -(sin2x)/2 + c
Have I calculated/approached this...
Wow, this is the first time I see a whole quadrant being in the graph, I would never have figured that out myself, thanks a lot for your clear explanation!
The equation is x-|x|=y-|y| and I need to make a graph for it.
So I thought I should solve it by breaking it down to 4 different equations, which would be -
x - x = y - y => 0=0
x - x = y + y => 0=2y => y = 0
x + x = y - y => 2x=0 => x = 0
x + x = y + y => 2x=2y => x = y
But this isn't...