Recent content by NoobieDoobie

When I had tried it, I first stared at the expression for ##\tan(\omega)## and concluded there's no way it can be as simple as the answer we're looking for. Now I understand why faith plays an important role. Thanks for the help!

That means I must be doing some trivial calculation mistake since I used same trig identity but my result doesn't match with ##\tan(\omega)##.

I'm not sure if it's necessary. I found exact formula for wigner rotation under two perpendicular boosts which turns out to be ##tan(\omega) == -\frac{\gamma_2\gamma_1\beta_2\beta_1}{\gamma_2+\gamma_1}##. Which gives the same result as Rindler under the limits ##\beta_1, \beta_2 << 1##. So we...

I am trying to work through rindler's relativity book. However, I got stuck at what I think should be a simple approximation. I calculated the angles ##\theta## and ##\theta''## using the formula for velocity transformation. If I simply expand ##\gamma(v)## and ##\gamma(v')## using taylor...