Calculate the area of the region bounded by the graph of the function y = 8 – 2x - x^2 and the x-axis
Y = 8 - 2- x^2
0 = 8 – 2 – x^2
(-x – 4)(x – 2)
- x – 4 = 0 and x – 2 = 0
-x = 4 x = 2
X = - 4
Do I do this?
Y = 8 -2x -x^2
= 8x - (2x^2)/2 - x^3/3
= 8 -...
Is this question correct? We are given to evaluate:
\int_0^2 \left(e^x-e^{-x}\right)^2\,dx
2\left(\frac{1}{2}\sinh(x)-x\right)
2\left(\frac{1}{2}\sinh(2\cdot2)-2\right)-2\left(\frac{1}{2}\sinh(2\cdot0)-0\right)
\sinh(4)-4
Can anyone tell me if this is correct?
\int
∫1 at top and -4 on bottom of symbol [1^3/3+3 1^2/2-(4 x 1)+C] - [〖-4〗^3/3+〖3x(-4)〗^2/2-(4 x-4)+C]
If f(x) = x^2+3x-4, then F(x) = x^3/3+3 x^2/2-4x+C
∫_(-4)^1[1^3/3+3 1^2/2-(4 x 1)+C] - [〖-4〗^3/3+〖3x(-4)〗^2/2-(4 x-4)+C]
[1/3+3/2-4+C] - [-64/3+24+16+C]...
Re: Stuck on this question please help
∫▒20/√t dt
20∫▒1/√t dt
20∫▒t^(-1/2) dt
40√t+c
Now subsitute in 10 to t and 21 into c
40√10+21
=147.4911064
So the slick will be 147 metres.
am I on the right track
Hi I am stuck on this integral question:
An oil tanker aground on a reef is losing oil and producing an oil slick that is radiating out at a rate approximated by the function (dr/dt)=20/√t, t is greater than or equal to 1 where r is the radius of the circular slick in metres after t minutes. If...
Hi, I am stuck on this question and was wondering if anyone could help me. The topic is integral equations.
A block of land is bounded by two fences running North-South 5 km apart a fence line which is approximated by the function N=0.5E and a road which is approximated by the curve...
it is given that the perimeter of the rectangle is (80 + 120 + 80 + 120) = 400 cm From this you need to make a cylinder with maximin volume:
400 = 2r + 2h
2h = 400 - 2r
h = 200 - r .
We wish to MAXIMIZE the total VOLUME of the resulting CYLINDER
V = πr^2 h
However, before we differentiate the...