So if I add the other kenetic energy to the other side of the equation I get kq^2/r(initial)=kq^2/r(final)+1/2mV^2+1/2mv^2. Instead of one unknown in the equation I now have two, the velocity of the second particle and the initial distance between the particles? How do I go about getting the...
One particle has a mass of 3.00x10^-3 kg and a charge of +7.80 µC. A second particle has a mass of 6.00x10^-3 kg and the same charge. The two particles are initially held in place and then released. The particles fly apart, and when the separation between them is 0.100 m, the speed of the...
A uniform electric field has a magnitude of 3.0x10^3 N/C. In a vacuum, a proton begins with a speed of 2.3x10^4 m/s and moves in the direction of this field. Find the speed of the proton after it has moved a distance of .003 m.
I try to work out the problem with the equation F=qE to find the...