Sorry, I don't think I was clear on what the problem is. Here it is: There are two people connected to a pully. One is holding the rope and touching the ground, the other is suspended in the air and hanging on to the pully. Both are perfectly still -- there is zero velocity.
Now, what I need to...
Oh yes, both persons are still. But if one person is pulling with a force of 700 N, shouldn't that accelerate the person on the other side of the pully of mass 60 kg?
Yes, thank you for simplifying things. The only thing I don't understand is, if person one (mass 70 kg) is pulling down on the rope with 700 N, shouldn't person two (mass 60 kg) be accelerated upward because of the net force of 100 N?
So the direction of friction is in the same direction as the centripetal force (which is the center of the record)? Shouldn't it be in the opposite direction because there has to be an equal and opposite reaction?
So then the forces for person one are 700 N upward and 700 N downward; and for person two 600 N upward and 600 N downward. I don't understand why they don't affect each other since they are both pulling down on the rope.
Thanks for posting. So the forces that act on person one are 600 N upward and 700 N downard; and for person two the forces are 700 N upward and 600 N downward. Does that sound right?
If a person of mass 70 kg is holding onto a rope that is connected to a pully and is suspending a person of mass 60 kg on the other side, what are the forces acting on each person. Oh, and both persons are still (0 velocity).
1) The hook exerts a force of 150 N on the rope. So would the tension in the rope just be 150 N? Or do you have to take into account the mass of the 10 kg rope, in which case the tension would be 250 N or 200 N?
2) The 6 kg mass does not have weight because it is suspended in the air, right?