Recent content by nblu

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    A question regarding kinematics

    Homework Statement A small plane flies a heading of 200km/h [W]. The wind speed is 50.0km/h [N] a) Determine the resultant groundspeed and direction of the plane b) What heading would the plane need to take to travel due west, and what would his ground speed be? Homework Equations...
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    Regarding Solenoid and Magnets

    Thank you rockfreak, for your comment. I'll make sure that I mention the polarity as well when I explain. :)
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    Regarding Solenoid and Magnets

    Hello, I was doing some questions and I thought I was understanding solenoids and magnets in incorrect way.. The question was, what would you feel if you bring a magnet close to a solenoid. I've wrote 2 possibilities, first is that they will repel and the second is that the solenoid would...
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    Regarding Gravitation and Gravitational Fields

    acceleration in free-fall is 9.8m/s/s right?
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    Regarding Gravitation and Gravitational Fields

    Homework Statement A satellite is designed to orbit Earth at an altitude above its surface that will place it in a gravitational field with a strength of 4.5N/kg. a) Calculate the distance above the surface of Earth at which the satellite must orbit. b) Assuming the orbit is circular...
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    Projectile Motion of a snowball

    oooh so since the kid is located 1.5m up, it would be 1.5 -1.2 = 30cm and that's the height the tree was hit with the snowball. i get it now! thanks for the looong two days of help :)
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    Projectile Motion of a snowball

    Thank You, So I used this equation to find the height at t = 0.5, \Deltad^{}_{y} = v^{}_{iy}\Deltat + 1/2a\Deltat^{2} since v^{}_{iy} = 0, \Deltad^{}_{y} = 1/2(-9.8m/s^{2})(0.5)^{2} \Deltad^{}_{y} = -1.2 m I get negative answer :( Did I use a wrong formula?
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    Projectile Motion of a snowball

    d_{x} = v_{x} x t t = 9.0 m / 18 m/s t = 0.5 s is this wrong?
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    Solving Kinematics Problems: Distance Traveled Before Applying Brakes

    Q: The average alcohol-free driver requires about 0.8 s to apply the brakes after seeing an emergency. Calculate the distance traveled after seeing the emergency before applying the brakes. with the question, the given speed is 17 m/s and t = 0.8. at first, i used d =vt equation to find the...
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    Projectile Motion of a snowball

    i'm sorry but i have no clue, i thought my answer to a) was right but since it's wrong i don't know where to start anymore..
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    Projectile Motion of a snowball

    oh you're right.. my bad, then I'm really stuck.. if my first answer was only telling "how long it will take for the snowball to hit ground", how can i find the tree's height and relate this equation to it?
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    Projectile Motion of a snowball

    oh oh, so I've used a different equation and i get a different t value, d_{x} = v_{ix} t + 1/2 a t^{2} 9.0m = (18m/s)(t) + 1/2(-9.8)(t^{2}) 9.0m = t(18m/s - 4.9m/s^{2} t) t = 0, OR 4.9m/s t = 18m/s t = 3.6 seconds would this be a new answer, or did i just do something stupid? lol
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    Projectile Motion of a snowball

    uh oh then I'm in a big trouble lol so I have to find how tall the tree is?
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    Projectile Motion of a snowball

    for c), i know that v_{fx} = v_{ix} = 18m/s, therefore, subsitute into v_{fy} = v_{iy} + a x t, since v_{iy} = 0, and a = -9.8m/s^{2}, i get; v_{fy} = -17.64 v_{f} = (18)^{2} + (-17.64)^{2} v_{f} = 25m/s tan\theta = 17.64 / 18 \theta = 44 degrees. Therefore, the velocity is 25 m/s...
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