Recent content by Naraliya

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    Solving for λ, a, and Vmax: An Analysis of Energy Balance and SHM

    Thank you, that makes sense. For your 2nd equation, what methods of integration did you use to get the 3rd? I can just about argue the first term because at t = 0, x is variable x to be incremented along until you get to t = t at which x becomes 3a. Not sure how you integrated the rest of the...
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    Solving for λ, a, and Vmax: An Analysis of Energy Balance and SHM

    It works! And it agrees with the answer I got when I used v = Aw! I can rest now. But first, time for some plenary learning. Your first force balance equation, what direction are you taking it from? From the ceiling or from point A which is 3a below the ceiling? Because I don't understand...
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    Solving for λ, a, and Vmax: An Analysis of Energy Balance and SHM

    So I'm not crazy then! And the max speed is simply V = wA?
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    Solving for λ, a, and Vmax: An Analysis of Energy Balance and SHM

    kmg is the modulus of elasticity, where k = 4/3 and is dimensionless.
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    Solving for λ, a, and Vmax: An Analysis of Energy Balance and SHM

    This is UK A-level Maths (mechanics). We don't deal with spring constants right now as our form of hooks law is actually ## T = \frac{\lambda x}{l_0} ## where ##\lambda## is the modulus of elasticity. But if that really is the amplitude of the motion between points A and B, then maximum speed...
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    Solving for λ, a, and Vmax: An Analysis of Energy Balance and SHM

    k = -10/3 when I plug in x = a/2 and v =0... My brain is exploding.
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    Solving for λ, a, and Vmax: An Analysis of Energy Balance and SHM

    Why doesn't it make sense? I wrote elastic energy = gravitational potential energy + kinetic energy. I can't see how its not dimensionally correct. And I know the amplitude of the oscillations. I worked out the equilibrium point and confirmed that the object should perform SHM between point...
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    Solving for λ, a, and Vmax: An Analysis of Energy Balance and SHM

    ## \frac {4/3 m g (2a)^2} {2a} = 5/4mga + 1/2mv^2 ## Elastic energy in spring at A = gain in potential to equilibrium point (3a to 7/4a) + kinetic energy built up in the mass during that motion. I get an answer of ## \sqrt{17/6ga} ## as the maximum speed. I don't think that's correct. From...
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    Solving for λ, a, and Vmax: An Analysis of Energy Balance and SHM

    a) λ = 4/3 by considering the energy balance as P moves from A (2a) to B (1/2a). The E.E. at A changes into a gain in gravitational potential energy + build up of E.E. at B since the spring compresses. b) a = 5/3g by considering that the mass P is in dynamic equilibrium immediately after...
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