Recent content by naftacher

I have seen this equation before. How am I to extend this to R3 and R4? or do I not need to

I am thinking that this circuit needs to be simplified somehow? Finding an equivalent resistance and moving from there?

I just wish that this absurd simple thing was not THIS dense to me.

this I understand. I just don't see "it", pardon the low IQ. This I cannot change. Somebody above did help me see the nodal definition of what is in series and what is in parallel. However, this was a redraw. From the original sketch, I would not have understood this.

Thank you for your redrawing. I do see that C4 and C5 are in series. and the intermediate connection C3 experiences with C4 and C5. However, in the original image I posted, this intermediate is just not obvious at all. Starting from the lower left node between C3 and C4, what is that...

Isn't there that same intermediate connection between C4 and C5 (that horizontal)? Therefore, C4 and C5 could not be in series with each other? I am so sorry. This never made sense to me.

I asserted C3, C4, and C5 to be in series. **I found the capacitance of "C3-4-5" to be 1.67x10-6 F. This I did by using 1/C = 1/C3 + 1/C4 + 1/C5 Then I noticed that I had another series circuit of "C3-4-5" and C1, and C2. Again, I used a similar formula. I obtained an equivalent capacitance of...