Haunted Mines Yes you are correct on that torque / force (see below ) as you point out -
Pkruse you are correct your way of looking at it makes it clear and simple and since you have worked at it so long what seems second nature to you takes me a bit of understanding. Also I like to...
HOw so?
If I understand it correctly torque consists of a measurement of force over a distance thus you have the pushing force on the lever. Simply we always look as the pushing force being 90 degrees that would be T=F * r where F = pushing force and r is the length of the lever. However that...
Yea I finally think I see what's going on
OK so if you look at my orginal drawing if i have the motor that has a 1 inch shaft and has 1000 ft lbs of torque that means it can pull at 1000 # at the shaft.
Ok put a 2" gear on that shaft - the torque is the same but since the lever arm is...
Hi Thanks for the response - I do see how you are stepping up the gears but let me ask you this. You say the first small sprocket sees the same torque as the motor
that has to be at the shaft not at the outside of the gear - I guess this is where I ma getting confused - torque must be measured...
Thanks for the response . Sorry about the letters. I have been reading about torque and I think I am beginning to understand it. Let me ask you this - is torque only measure at the shaft ?
If that is the case then I can see how torque at the shaft never changes. If I understand it correctly...
HI:
Thanks for your answer. I guess this is where I am getting confused - you say that changing shaft diameter will not affect torque -
This is what I don't understand - on the last pulley if I had a 1" shaft sticking out you are saying that this 1" shaft will pull with the same force as a...
Hi Guys :
I have been reading about torque and gears and not being an engineer or physicist would like to know if my thinking is correct in the following example
Ok so Say I have a hydraulic motor and it generates 3000 ft lbs of torque and it is going to be turned at 650 RPM (tractor...
Hi Guys!
Thanks for all of the great input. I ma sure I am going to have more questions when it comes to making up the circuit. IN the meantime I have done a lot of reading and have gotten the calculations down especially the torque reduction. I agree that using a high torque low rpm motor...
Hi Guys!
Thanks for all of the great input. I ma sure I am going to have more questions when it comes to making up the circuit. IN the meantime I have done a lot of reading and have gotten the calculations down especially the torque reduction. I agree that using a high torque low rpm motor...
Yes I did misunderstand lol ! I shoudl listen first then type! I think iI see what you are saying - basically the most force would be required to break the log out of its inertia and into movement.
This would be less than 10,000# because we are not lifting it but rather rolling it (?)...
Yes I absolutely agree there will be more force necessary initially to overcome the inertia of the "dead" weight and any resistance to movement. What that is I do not know but will factot hat into the equation. I have also figured out my calculations for torque reduction with the motor and...
I am planning to take the conveyor and then dump it into bins - I will then be able to lift the bins with my tractor (so there is no stacking) . Then when i need fuel for my outdoor boiler i Just pick up a whole bin and move it - a lot less labor
as far as dramatic here's an OSHA approved one...
HI:
Here is an example of what I wish to make:
The above calculation would be for the motor that is moving the log forward. There would actually be several hydraulic motors and cylinders as follows
MOtors;
1.) To move log forward
2.) To run chainsaw
3.) To run a conveyor...
no problem - thought you were making fun of my grammar - in building we often say foot as a collection of single units even thought the proper term is feet
now can anyone look at those calculations my back won't hold out through another firewood season ! LOL