Hello.
My attempt at the solution is as follows:
l = 160m
Q= 300 ls-1
R= p2/p1= 6+1.01/1.01 = 6.94 (2dp)
d = Unknown
Pressure drop = 0.3 Bar
0.3 = 800*160*300^2/6.94*d^5.31
0.3 = 1.152x10^10/6.94*d^5.31
0.3 ( 6.94*d^5.31) = 1.152x10^10
6.94*d^5.31 = 1.152x10^10/0.3
d^5.31 =...