Thanks goktr001, but i have just solved it, its actually 44.
I summed the area under the graph, but only till the 11sec, i didnt notice that 11.5 is actually 3 quarders of triangle.
Problem solved anyway. thanks.
Homework Statement
A velocity of a runner is described in the graph below. The runner started from X=0 on the X axis. In what distance from X=0 (beggining) will be the runner, after 11.5 sec.
Homework Equations
The Attempt at a Solution
Please tell me why it isn't 42m.:confused:
you mean this?:
1/f=1/U+1/V
i used this for the lens 1, and found that V, image distance, is 12, which means it is located 6 to the negative's right, 2 after the focal point.
So how can i use the equation for the second lens? U is supposed to be an object, not converging rays.
Homework Statement
S is a lighted object, height=1.
what is the final image that is created by the system?
Homework Equations
The Attempt at a Solution
i just don't understand how do i find the location of a virtual image created by a negative lens when the rays converge to a...