I'm not going to lie, I have no idea what any of this means. All I know is that I was asked to find a method to figure out the single candy mass of it. Doing Calculus next semester so don't have too much into mathematics.
Using the empty bag of 10g, I can make this cost function:
total mass = 10g + (x)m
so,
38 = 10g + (x)m
90 = 10g + (x)m
62 = 10g + (x)m
30 = 10g + (x)m
where m is the mass , 4g/n, for any positive integer n. And x is the number of additional units.
Neither of those are very likely, especially comparing to the probability of it being 4g. If 4g, then there are both even and odd amounts of candy in different bags , and it contains no higher divisors. I just dislike using probability to answer a 'determine' question, also without using...
I am trying to read into the assumptions Millikan made prior to the experiment regarding electrons, but can't find it. As far as Masses that work; 1g, 2g, and 4g. As far as finding the greatest mass the single candy could be, the greatest divisor would have to be contained in the smallest total...
[Mentors' note: There's no template because this thread was moved from General Physics. The specification of the problem seems adequate without the template]
Hi everyone,
I am working through stuff based on the Millikan Oil Drop experiment. There is a question that asks to determine the mass...