Ohhh, I was always under the assumption that once you decompose the force vector, its decomposed vectors must exist as a force acting on the block.
So what you mean is: A surface moving along its own direction underneath another object, cannot possibly exist a force on that object due to the...
True, but what makes Ffriction the same as Fparallel of the plane? Both forces do act in the same direction, but that doesn't mean that they are the same force. Yes, Ffriction is 0 because the coefficient of friction is 0, but that doesn't imply the force of the parallel component is zero. If a...
Ah, thank you! That's really clear explanation.
"The component parallel to the surface is also called the friction force."
-I thought the friction force would be in response, but in the opposite direction, to the parallel component of the plane. So while a Ffriction does not exist, the...
Yeah, under the assumption that it is perpendicular, the problem makes sense and I understand how to finish it. The answer key always had the correct force diagram so I know what it looks like, I just drew mine to emphasize my thought process.
Can you elaborate on: "Here it must be...
Oh, so is my mistake the direction of the inclined plane force? While I drew it to be completely horizontal, the force of the inclined plane on the block is actually perpendicular to the inclined plane's surface?
It's kind of hard for me to understand why that is the case. Since the...
I don't see how this situation is the same because the ramp is frictionless and the only reason the block stays on is because the moving plane moves the block upwards. But whenever I try drawing a force diagram, there is no force vector pointing upwards.
Homework Statement
A block lies on an inclined plane with an angle of elevation theta. The inclined plane is frictionless, and the plane is accelerated to the left such that the block's height remains constant. What is the net force on the block?
I'm having trouble figuring out how to draw the...