Recent content by Minescrushessouls

  1. M

    Thermodynamics: Compression of an Adiabatic Gas

    So ΔU=-PΔV, where U=w But the problem isn't isobaric, so that equation wouldn't work. I can't seem to find another equation though...
  2. M

    Thermodynamics: Compression of an Adiabatic Gas

    Homework Statement Assume 1.500 mol of a monatomic ideal gas is compressed from 3.00 L to 1.00 L. a. If the initial and final temperature is 10.0 °C, what are the initial and final pressures (in atm)? b. How much work input (in kJ) is required if a reversible isothermal path at 10.0 °C is...
  3. M

    Parallel Axis Theorem- Composite Areas (STATICS)

    You're probably 100 percent right. I didn't read the question well enough
  4. M

    Parallel Axis Theorem- Composite Areas (STATICS)

    Homework Statement Consider the beam shown in (Figure 1) . Suppose that a = 15 in. , b = 8 in. , c = 1 in., and d = 4 in. Determine the moment of inertia for the beam's cross-sectional area about the x axis...
  5. M

    Radio Broadcast Antenna Peak Intensity

    So the area would be the area of a circle, or pi*r^2 So would that mean it would be W/(pi*r^2)?
  6. M

    Radio Broadcast Antenna Peak Intensity

    Ok so S=(ExB)/μ But how would I find E and B from the information provided?
  7. M

    Radio Broadcast Antenna Peak Intensity

    Homework Statement A radio broadcast antenna is located at the top of a steep tall mountain. The antenna is broadcasting 104.3 FM (in Megahertz) with a power of 5.00 kilowatts. What is the peak intensity of the signal at a receiving antenna located 25.0 km away? Homework Equations Honestly...
  8. M

    Concentric Coils EMF from Graph

    Thank you so much for all your help!
  9. M

    Concentric Coils EMF from Graph

    That's the expression for flux. I would need to use the area of the small coil because that is what experiencing the induced emf. So Na*Nb*pi*Rb^2*μ*5e^(-(t-6)/2))/2Ra is the flux, and the time derivative will be the induced emf in the small coil
  10. M

    Concentric Coils EMF from Graph

    Ok... So would the correct equation be: Na*Nb*pi*Ra^2*μ*5e^(-(t-6)/2))/2Ra And then take the derivative with respect to time and plug in whatever value for t? I think I understand the concept.
  11. M

    Concentric Coils EMF from Graph

    Oh! The magnetic field created by the large coil. So I need to multiple in dA, which would be 2*pi*r to get flux. Then I can take the time derivative to get emf
  12. M

    Concentric Coils EMF from Graph

    The flux of the large coil, with current as a function When the derivative is taken with respect to time, its the emf in the large coil
  13. M

    Concentric Coils EMF from Graph

    Oh ok, I must have missed that. So it would be d/dt(μ*5e^(-(t-6)/2))/2Ra? Does that make sense? That would be the emf in the large coil, but how do I translate that into induced emf for the smaller one? Or is it all the same?
  14. M

    Concentric Coils EMF from Graph

    The flux with respect to time, is that where the graph comes into play?
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