Recent content by Mightiestmike

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    What is the Time of Collision for Two Vertically Launched Objects?

    Givens: Via1 = 25 m/s a = -9.81m/s^2 Vfa1 = 0 m/s Via2 = ? da1 = ? Vf^2 = Vi^2 + 2ada1 0^2 = 25^2 + 2(-9.81)da1 -625 = -19.62da1 da1 = 31.85524 m Therefore Half the height = 15.92762 m Need Help Continuing
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    What is the Time of Collision for Two Vertically Launched Objects?

    Pat shoots an arrow vertically upward with an initial speed of 25 m/s. When it is exactly halfway to the peak of its flight, he shoots a second arrow vertically upward from the same spot. They collide just as the first arrow reaches its highest point. (A) What is the Launch Speed of the...
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    Ropes Pulleys Help Exam 2morrow

    Solved it! I think. For the Mass on the Surface: a = (T - Ff) / m1 For the Mass suspended in the air: a = (Fg - T) / m2 I am not sure which is correct, is a = (Fg - T) / m2 correct and you don't take m1 into account because the force on that is caused by T which is...
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    Ropes Pulleys Help Exam 2morrow

    Ok, if you had a question where a cart (m1) is resting on a surface, and is attached to a string passing over a frictionless pulley, off of which another mass (m2) is suspended in the air, what is the equation that I use? It is like an atwood machine, except m1 is on a surface, and, I need to...
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