well.. apparently , they didn't change the policy , but after u access the link , you should fill an application so that they can send u an e-mail that allows u to download it for free . I didn't get any ! that's what the problem is ...
thanks for ur replies
Well ...I can access to the cadence link , but after i clicked on the Orcad link and tried to sbmit a request to get the Demo cd , i filled the application , and waited for an e-mail adress that should be delivered to my inbox that allows me to download the Demo , but there is no reply from the...
PSpice software needed :(
hey guys. i urgently need the Orcad Pspice software :( please if anyone has a link from which i can download the software , i would be very thankfull ...
P.S this link http://www.cadence.com/products/si_pk_bd/pspice.aspx is not working ...
Thanks...
Can anyone please tell me from where can i download the Orcad PSpice software ? i really need it...
I would be thankfull if you give me links ...
thanks
Can two resistors in series be replaced by a single resistor and give an equivalent resistance to the circuit?
My answer is yes they can be replaced by a single equivalent resistance
buthow must the single resistance be related to the two in series ?
will it be in series !?
If an ammeter is connected to the negative terminal of a battery,so it is on the opposite end of the line from where the current leaves the battery and enters the circuit,right?So Why, in a series circuit, the meter needle jumps to it's full value instantaneously with the closing of the switch ...
When resistors are connected in parallel, which one , according to resistance value, carries the larger proportion of the currents? Does the ratio appear to be directly, or inversely, proportional to the ratio of the resistances?
Can two resistors in series be replaced by a single resistor and give an equivalent resistance to the circuit?
If so , how must the single resistance be related to the two in series ?
R=R1+R2 ? ?
Hey i have a little question to ask... when a series circuit is broken (disconnected) at the negative terminal of the ammeter , does the charge flow around the circuit until it gets to the end of the line at the ammeter and then stop ? or does it stop at the moment when it's broken?
hey...we've done few days ago a physics lab experiment about the equipotential lines and electric field where we used the following apparatus:
a 6-volts battery , contact switch, wooden board with spring contacts, hand probe, fixed probe,galvanometer,resistance box,wires and conducting papers...