You may need to run a few simultaneous equations. Here's my suggestion: Use the generic information provided to solve for Is and VT before proceeding further. Then from there you can solve for R using the fact that both sides of the circuit must equate 10mA.
Circuit B is definitely interesting in the way its drawn, but what if you were to draw a resister in Circuit B where the resistor is in Circuit A, and label it 0 Ohms. Does that help change your understanding of the circuit? Can an electron find a way to move from the voltage source through both...
Hi aishax, welcome to PF.
Start with drawing some free-body diagrams:
- One of the complete system (A + B)
- One of A only
- One of B only
Hint: The force felt by B must be the amount that makes it accelerate at the same rate as A and as A+B.
What are the "external forces" in each case?
You've got to a good start by correctly understanding that both particles are moving at constant "velocity". What you don't mention is... what velocity? The same linear or angular velocity?
;-)
Acceleration vectors can be added together using the same math as you've been using to add velocity vectors. You do not need to really break the components up into x-y, because you already know the direction of the acceleration!
1. Due to gravity directly down (-y).
2. Due to the plane directly...
How are you arriving at these numbers? Also please see the forum guidelines on homework problems.
Properly solved, this problem requires some integration.
Since wave speed doesn't depend on the x-position, you can zero it and remove it from the equation, then you are left with a simple: y= f(t) relationship.
Recalling some calculus and allowing me to rephrase the question should do the trick. What is the rate of change dy/dt when y is 12.
Can you clarify the question again? Are you looking for distance from the dock or time?
In my understanding of the question, when the boat is released from the dock, the boat is stationary with respect to the child. Then it's a matter of just directly driving to the child.
Could I get confirmation on this question? Normally when electric dipoles are talked of, we would look to find fields for distances perpendicular to the dipole rather than parallel.
For the 1st question, review the kinematics equations again. There is an equation where displacement is expressed as a function of: initial velocity, gravity, and time. By equating this displacement, you can then solve for the time.
For the 2nd question, you are right on!
I think it will be easier for us to see where you went wrong if you would show some work with regard to the step on substituting the value of Twb.
My suggestion to get Tbd, now that you have the tension in the rope right is to take the moments at A. The sum of moments must be zero. You have a...
No, I had meant that for your previous comment, below saying "long and drawn out". I was supposing all physics problems are "long and drawn out" =P. Now looking at your work, your algebra is fine ^^. Sorry if it didn't really get across right.