Recent content by Meteo

0.250 mol of a monatomic gas follows the process shown in the figure. How much heat energy is transferred to or from the gas during process 1 to 2? How much heat energy is transferred to or from the gas during process 2 to 3? What is the total change in thermal energy of the gas? I am not...

Your younger brother is supposed to mow the lawn using a push mower. He reasons from the Newton's Third Law that the mower will push back with the same force he exerts on the mower; therefore nothing will move and attempting to mow the lawn is pointless. What is wrong with his reasoning? a: The...

In this experiment, we had a half meterstick with a hole at one end. This was the pivot point. Then about 4 cm from the pivot point was a scale which suspended the meterstick horizontally. Then we had an unknown weight at the other end of the meterstick and we measured the force on the scale...

why is m2 accelerated upwards at g? its weight will be m2g... so T=2m_2g? I think I am comfused on what tension is...so the force of it pulling up and the force of the weight pulling down = tension?

An atwood machine holds two masses at its ends by a massless rope. m1 and m2. Assume the pully is frictionless. What will the magnitude of the tension(T) go to as m1 goes to infinity but m2 stays the same? Im very lost on this problem. I have drawn a free body diagram showing m1g and m2g...

Yes, it is an inelastic collision. Also a separate question is what would the difference between an elastic and inelastic collision?

Theres some calculations in this problem that I just don't get... Start with the equations for initial and final momenta and kinetic energies and derive the theoretical equation for the ratio fo K_f to K_i P_i=Mv_i P_f=(M+m)v_f K_i=1/2Mv_i^2 K_f=1/2(M+m)V_f^2...

Yes, that's what I managed to get. I think the mgtan(\theta) must be a mistake the teacher made since \mu cannot equal mgtan(\theta) because its dimensionless as AM said.

I have a box at rest on a plane raised to the critical angle. I need to derive the formula \mu_s=mgtan(\theta) I know f_s/n=\mu n=f_y=mgcos(\theta) f_s=f_x=mgsin(\theta) This leaves me with tan(\theta)=\mu cause the mg cancel out... what did I do wrong?

Ah ok I see why my answer is wrong. I needed to subtract weight from the thrust.

A couple of questions in this problem. A 20,000kg rocket has a rocket motor that generates 3.0 *10^5N of thrust. 1. What is the rocket's initial upward acceleration? I used the formula F=MA and got 15 but apparently that's not the right answer. So I am stumped. 2. At an altitude of...

The questions for problem 2 were find the acceleration of the rocket, then find the velocity as it passes 5100m. I labeled v0=t0=y0=0 y2=5100 t1=16 t2=20 Using the equations I got V1=16a Y1=128a I then used the 2nd equation 5100=128a+16a(4)+1/2(-9.8)4^2 I get a=26.9 :smile...

Right now I've only learned 3 equations dealing with constant accleration v_f=v_i+a_s\Delta t s_f=s_i+v_i\Delta t+1/2a_s(\Delta t)^2 v_f^2=v_i^2+2a_s\Delta s Ok first problem: A Porsche challenges a Honda to a 400-m race. Because the Porsche's acceleration of 3.5m/s^2 is...