Yes it is very similar to our lecture slides. Unfortunately I can't tell from my cam what the type of motion each segment is unless I simulate it. And I can't simulate it without knowing what type of motion each segment is. That is why I am asking someone with a bit more knowledge about cams...
I have designed this one. But I don't know the terms for what type of motion each segment is. I would like to know it so I can recreate it in the program I took a screenshot of above. In the program they don't use the information I was given, like rise angle, return angle, nose size etc. They...
As I also said above, I DESIGNED THIS CAM. I have all the measurements, it is a four arc cam, with each arc tangent to the next. That picture is a screenshot of the one I made on the computer. I made it from the information I was given, the rise angle, return angle, nose radius, base radius and...
I just want to know what type of motion the cam segments are. The first, base circle is clearly a dwell motion. What is the next called? Is it a constant acceleration, harmonic, double harmonic etc.? And what is the nose? It isn't a dwell or harmonic.
This is a cam I designed from given data. I know all the measurements but I just don't know how to make it using the Solidworks cam design tool as I don't know what the names are for each section. That's all I need, what each arc section is called as per the names in the dropdown box
I am trying to determine what type of cam this is from the various cam diagrams but they don't really help as they all seem very similar. I have a simple four arc cam, so a base circle/arc, a nose circle/arc and an arc on one side tangent to the nose and base arcs, and another of slightly...
This is what I am putting into Wolfram Alpha - 'definite integral of (500x^(1/3))/((0.00175x)(2.2x10^(11)x)) between 0 and 1.5'
However I don't know how to interpret the answer...
This is what I am putting into Wolfram Alpha - 'definite integral of (500x^(1/3))/((0.00175x)(2.2x10^(11)x)) between 0 and 1.5'
However I don't know how to interpret the answer...
Yes thank you, I just found the right formula to use. It states the displacement is = integral between 0 and L of P(x)/A(x)E(x)
However I still don't know how to do it unfortunately. They give me w in the diagram, is this supposed to be P in the equation? And how would you substitute x in? Do...