a little confused
i tried the first part but I'm not sure if this is what you meant...
molecular weight of water = 18 g/mol = .018 kg/mol
then:
2(.018kg/mol) = .036 hydrogen atoms in 1 kg of water
4kg(.036) = .144 hydrogen atoms in 4 kg of water
.00015(.144) = 2.16e-15 number of...
this is homework problem I'm having some trouble with... i haven't had chemistry yet so I'm not sure how i could convert atoms into kg, and the textbook i have doesn't do any examples of problems like this one... i don't even know where to begin.
Deuterium (A=2, Z=1) is an attractive fuel for...
ok i think i finally understand how to find R now...
R= .027
once i figured that out, i did:
I=emf/R = (-708)/.027 = -26266.1
P=I(emf) = (-26266.1)(-708) = 18596420.37W
E=Pt = (18596420.37W)(.45s) = 8368389.167J and that should give me the electrical energy dissipated in the wire right...
won't that give me units of ohm/m^2 ? i thought i was supposed to be getting rid of the m's because the R is in units of ohm...
i'm still very confused about this problem.
The coil of a generator has a radius of 0.14 m. When this coil is unwound, the wire from which it is made has a length of 5.4 m. The magnetic field of the generator is 0.10 T, and the coil rotates at an angular speed of 35 rad/s. What is the peak emf of this generator?
so i have:
r= .14m
L=...
A piece of copper wire is formed into a single circular loop of radius 13 cm. A magnetic field is oriented parallel to the normal to the loop, and it increases from 0 to 0.60 T in a time of 0.45 s. The wire has a resistance per unit length of 3.3 x 10-2 ohm/m. What is the average electrical...
so it would be like this? mass + k|q1||q2|/r^2\sin = E + mg/cos ?
which would give me... (6.70e-3)((((8.99e9)(150000)q2)/(r^2))/sin 30) = (8.436)(.0758)?
i would be solving for q2 right? but what about r^2, what would i make that?
-annie
A small plastic ball of mass 6.70×10-3 kg and charge +.0150 uC is suspended from an insulating thread and hangs between the plates of a capacitor. The ball is in equilibrium, with the thread making an angle of 30.0° with respect to the vertical. The area of each plate is 0.0200 m^2. What is the...
this is what i tried ((8.99e9)(2.2e-12))/((3.0e-2)^2) and i got 21.976... so now am i supposed to multiply by 4? cause that answer i got isn't right
-annie
Four point charges have the same magnitude of 2.2 10-12 C and are fixed to the corners of a square that is 3.0 cm on a side. Three of the charges are positive and one is negative. Determine the magnitude of the net electric field that exists at the center of the square.
i tried using...
you guys are awsome thanks so much... i understand what i was doing wrong now, i just didn't understand holly's explanation correctly... we've never learned that gravity could be anything besides 9.81. :)
whouldn't it just be easier if i took the derivative of this: h(t)=5.9+69t-16t^2
so: h(t)'=69-32t
but what do i do from here to get the max height? our physics teacher has only taught us using formulas...
ok so i understand why i shouldn't included gravity in this but how else can i solve for t?? i think I'm making this much harder than it should be, but i never learned anything about kinematics...