Recent content by Martyn Arthur

  1. M

    I Why on Earth do we not see older stars close to us?

    Thank you for a brilliant answer to a dumb question for which I offer my apologies. Thanks Martyn
  2. M

    I Why on Earth do we not see older stars close to us?

    Phares as pragmatically as I can, thus leaving aside observational issues such as light speed, Universe expansion, moving apart galaxies and the Universe having no edge. Focusing on the fact that an observer on Earth looking deep into space can effectivly see the oldest stars formed during the...
  3. M

    Classification of Equlibrium Points

    Its just so frustratting and unneccsary. Just an ancilliary, mt lab partner (an English Teacher) and I did a 90 hour experiment following explicitly the instructions given. We downloaded the data and inspected the files without finding the required data My lab partner contacted his tutor, mine...
  4. M

    Classification of Equlibrium Points

    Would it be ok if I rework each of the sessions and check with you (with proper data) that I have an understanding? I don't want to knock the OU system, itsmy University, but in large part it relies on peer to peer analysis - v - actual consulation and checking witha tutor. Its ok but then...
  5. M

    Classification of Equlibrium Points

    Reviewing; I am wasting your time sorry. I have six weeks to get on top of this. I need to get back to basics and work through piece by piece. Maybe I can take a rain check with you at those stages please. Thanks
  6. M

    Classification of Equlibrium Points

    Thanks; I will check it and improve my handwriting; I have looked at latex but I am finding the course difficult and struggling to find time to learn something else just now. I did look at the video; he seems to be approaching the Jacobian maitrix differently from my tutor. My overall question...
  7. M

    Classification of Equlibrium Points

    Herem from the video I am unclear about the process, are the functions f and g being integrated to their original form and the differentiated to find the partial derivatives? Thanks Martyn
  8. M

    Classification of Equlibrium Points

    Thanks; hopefully this gets it and I can move to the Jacobian Maitrix?
  9. M

    Classification of Equlibrium Points

    Have I correctly calculated the elements that I need to use for the eigenvecor calculation as dx/dt =-y +1 the elements are -y as a constant and 1 with y differentiated. for dy/dt = x^2 - y^2 the elements are -2y with x ignored as a constant and 2x with -2y ignored as a constant. Thanks Martyn
  10. M

    Classification of Equlibrium Points

    I hope this is more properly laid out? We previously established that the stationery points were (1,1) and (-1,1) For this first stage I now need to create the elements of a Jacobian maitrix using partial differentation. I am confused by reference to the chain rule. Am I correct that for dx/dt...
  11. M

    Understanding Equlibrium Points; differential equations

    Apologies, the question should have been accompanied by my workings I will try again shortle.
  12. M

    Understanding Equlibrium Points; differential equations

    Following on am I correct in saying that for the Jacobian maitrix the partial derivatives of dee u / dee/x and dee u / dee y are -y and 1 respectively and the partial derivatives of dee v / dee/x and dee v / dee y are -2y and 2x respectively?
  13. M

    Understanding Equlibrium Points; differential equations

    AH substituting 1 for y^2 and factorising gives me , for x +/-1 So thus, I believe we have (-1,1) and (1,1) Thank you, onwards to the Jacobian maitrix. Martyn
  14. M

    Understanding Equlibrium Points; differential equations

    Thank you.... x^2 =1 so x =1 not +/-1 just 1 as per my calculator. I hate blaming ADHD, I rate quite high on chess.com its ridiculous but on occasions I get into this situation. We have an x value of 1 I need to fit it in here, but can't see how dx/dt =1-y (1)
  15. M

    Understanding Equlibrium Points; differential equations

    For dx/dt = 0 (1) 1-y =0 , y= 1 substituting For dy/dt = 0 (1) for dy/dt x= sqrt 1 =1 so I have points (0,1) and (0,1) But this isn't correct! 'cant figure out where to go from here? Thanks Martyn
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