Recent content by mandy9008

  1. M

    Finding speed of a string given length, mass, and velocity of wave

    Homework Statement A string is 50.0 cm long and has a mass of 3.0 g. A wave travels at 5.0 m/s along the string. A second string has the same length, but half of the mass of the first. If the two strings are under the same tension, what is the speed of the second string? The Attempt at a...
  2. M

    Isotope Stability: Why Rhodium is Important in Brachytherapy

    Homework Statement Why is it important in brachytherapy to realize that rhodium is not a stable isotope? If rhodium were not a stable isotope, what considerations must one make? I know that a stable isotope can go from one element to another, but I don't see how that would have anything to...
  3. M

    Unraveling the Mystery of Neutrons in Fission Reactions

    Homework Statement Fission reaction: 10n + 23592U --> 14156 + 9236 Kr + 3(10n) Why in the world is there a neutron on the left side of this rxn? Why not just reduce the number of neutrons on the right side to two?
  4. M

    Questions About Ruthenium 106 and Brachytherapy

    Homework Statement 1. Ruthenium 106 is used in brachytherapy. It has a half-life of 1.02 years. Ruthenium 106 decays by beta emission (e-) to rhodium 106. The mass of ruthenium 106 is 105.907330 u and the mass of rhodium 106 is 105.907288 u. Rhodium 106 is not a stable isotope of...
  5. M

    Calculating Buoyancy in a Disaster Survivor Scenario

    okay, i was just using the wrong buoyancy force. Thanks! :)
  6. M

    Calculating Buoyancy in a Disaster Survivor Scenario

    Using the value of B and the weight w of the survivor, calculate the weight wr of the Styrofoam. B=w + w_r 1044.68N = 617.4N + w_r w_r = 427.3 N What is the density of the Styrofoam? ρ=m/v ρ=(43.6 kg) / 0.16 m3 ρ=272.5 kg/m3 What is the maximum buoyant force, corresponding to...
  7. M

    Calculating Buoyancy in a Disaster Survivor Scenario

    i just figured it out. 2m x 2m x 0.026m = 0.104m3
  8. M

    Calculating Buoyancy in a Disaster Survivor Scenario

    the only equation in my textbook i can find shows this: ρobject / ρfluid = Vfluid / Vobject
  9. M

    Calculating Buoyancy in a Disaster Survivor Scenario

    the volume I used was the volume of the block. when it is put in the water, 0.026m of it is submerged. does this mean that i need to subtract this value from the volume of the block?
  10. M

    Calculating Buoyancy in a Disaster Survivor Scenario

    i just found another equation for B that my prof gave me. It is B=ρVg. B=(1025 kg/m3)(0.16m3)(9.8m/s2) B=1607.2N this is wrong though
  11. M

    Calculating Buoyancy in a Disaster Survivor Scenario

    I do, but I figured that, since I was asked to provide the equation for Fy (B-w-w_r), I would need to use that. Is this not the case? I know: V = 0.16 m3 ΔV = 0.026 m m = 63 kg In order to use the bulk modulus, I need to know P. Do i just use P for water?
  12. M

    Calculating Buoyancy in a Disaster Survivor Scenario

    Homework Statement A 63 kg survivor of a cruise line disaster rests atop a block of Styrofoam insulation, using it as a raft. The Styrofoam has dimensions 2.00 m multiplied by 2.00 m multiplied by 0.04 m. The bottom 0.026 m of the raft is submerged. Write Newton's second law for the system...
  13. M

    How Does Pressure Affect Water Density in the Mariana Trench?

    yes, i did copy part a wrong. the question for part a was: (a) Calculate the change in volume of 1.00 m3 of water carried from the surface to the bottom of the Pacific. so, if the density is different, how do i determine the change?
  14. M

    How Does Pressure Affect Water Density in the Mariana Trench?

    Homework Statement The deepest point in the ocean is in the Mariana Trench, about 11 km deep. The pressure at that point is huge, about 1.13 x108 N/m2. (a) The deepest point in the ocean is in the Mariana Trench, about 11 km deep. The pressure at that point is huge, about 1.13 x108 N/m2...
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