Recent content by MaisieMitchell

Thanks all. Following on from plenty of googling about it I now understand the question. Appreciate all the help and guidance.

Stuck with i & ii can somebody please guide me. none of my coursework material has anything similar in to help me work this one out.

Thanks again!

Thanks, when you say about the same result - is there something that I have missed?

Correct part D is the question sorry - Estimate the rate of heat loss by natural convection to the atmosphere by each metre length of pipe. The equation for doing this is Q=hA(DeltaT) therefore.. Q=h(2Pi*rL)(DeltaT) Q=1.34*(90-14/0.1)^0.25 *0.1*Pi * 1 * (90-14) Q = 167.9855 w/m

Does this working out look okay? Thanks in advance.