Recent content by Mahfuz_Saim

As it is on the left side, they will meet at a point which is 2.4 m away from A. And the minimum height of the block should be 4.7995 m. (If I have not done any mathematical error). Thanks.

One more thing, do I need to add the value of x with AB or subtract in order to get the distance from A and why? Please answer.

Okay, thank you very much, @hutchphd . This was my second question here and have learned a lot from it.

Yes, I want to add that with my answer. Please make an answer to my last question. Thank you.

By using v= ω√(A^2-x^2), I will get a value of x. Do I need to add with the distance of AB? As the block is stretched, I think I need to add the value of x as I am keeping the value of A positive. Am I right? Please reply. Thank you.

The angle is 60°. So, sin120°= √3/2. Am I correct?

If I am not wrong, the horizontal range= (v^2*sin2θ)/g. Then it will be 11.08. So, the pebble will land 11.085 m away from C. Is it correct? Please tell me if I am going in the right way or not. If not, please tell me the right way to solve this question.

Okay, but I am not talking about the width. The main problem is with hight. If I consider the block as a point, the question becomes meaningless as the projectile's range is more than AC.

@haruspex, do I need to use δ= π/2? Maybe, yes. Why? @Delta2, there is nothing about the hight in the question. That's more confusing. The range of the projectile is more than the distance of AC. So, maybe if they stay at the same point on t= 1 sec, maybe the answer will be yes. Please let me...

Question 1: I have used v= Aω*cos(ωt+δ) where A= 0.2 m, ω= π/3, t=1 and δ=0. Are the values right in this case? I am confused. Question 2: From question 1 I have got the value of V which is 9 m/s. By using v= ω√(A^2-x^2), I have got the value of x. Now, do I need to add it with 2.5(distance...

Thank you very much. It was my first question here and have learned a lot from it. Maybe I will ask some more question in the near future.

I think I have got it. They have used m=M/Avogadro number. Am I right?

But they have considered m= 28*10^-3. Maybe they are considering it for Nitrogen gas. That's why I am saying that it can be 32*10^-3 for oxygen. I don't know whether it will be a good idea or not but can you tell me the value of each variable of the equation according to my question. Maybe I...

Thank you for your help. Can you please help a little more? The pressure is given in the question which is 1 atm equals to 101325 Pa. But I don't think that is the correct value of p. If you check the link again, you will see that they have considered P as a product of Avogadro number and...

Please answer these questions in the picture. Thank you.