Hello,
I'm trying to design a capacitor charging circuit using a Cockroft-walton voltage doubler circuit.
My mains voltage is ~220 Volts and the output would be 220*2 = 440.
My capacitors are rated for 500V which means that they can be charged safely to about 400V.
Is there a circuit...
well, I asked this question because I'm building a simple DIY coilgun.. (just 8J of energy stored in the caps). So I'm going to have to resort to trial-and-error. Thanks for your help.
Thanks for the reply.
Yup, the calculations do seem to be complex and even then, if the equations are solved, they only give rough estimates. :(
Trial and error it is then..
oh well..
Just for the sake of knowledge, does the gradient of the field come into play because all magnets have two poles and because the net force depends on the difference between the force on each end?
Homework Statement
A prallel plate capacitor placed in air has a plate area A and a plate separation d. It is cahred to charge Q by connecting a constant foltage source across the plates. The voltage source is then disconnected and a slab of dielectric constant K and thickness h is inserted...
lol... ok then.
Let's say for theoretical purposes that a cell had 0 resistance.
Kirchoff's second law says that the algebraic sum of potential differences around a closed loop is 0. The (imaginary) batteries maintain a constant voltage across their terminals. So shouldn't we be able to apply...
Homework Statement
Find the Voltage across A B in the following circuit. Each cells has negligible internal resistance and an EMF of E volts.
(First diagram in the attached picture)
Homework Equations
I'm trying to use Kirchoff's second law.
The Attempt at a Solution
Now, if I...
Why is it that simple balances always come to rest in a horizontal position when equal weights are placed on both ends? If the weights are equal, then (assuming that the distance from each weight to the pivot is the same) the torques produced by the weights are equal and opposite and the net...
This thread look to be long dead... however, I did find it useful. I had the same question (more or less) as the OP and post #4 did a good job of explaining things. Thanks Doc Al.