Ok! So if I understand correctly, Fpiston * 5 meters will give me a result in N m, since Force * Distance = Torque, which is measured in N m, right?
Sorry to ask all these questions, but I feel like I'm close to understanding it and I want to make sure I do!
Thanks voko!
Aaah good, I now understand. One more thing, is Fpiston in Newton meter, which means that if I need to push the piston over 5 meters, I'll have to multiply Fpiston by 5 to know how much energy I used in total?
Thanks again, voko.
Still in relation with this situation, I've figured out that the formula Fpiston = 1/2 ρgwh2 can help with determining the force acting against the piston. I am a bit confused though, because even though I know the value of each of these factors, they have a different...
Ok great, thanks for the clarifications. So just to make sure I understand the concept of hydrostatic pressure correctly: hydrostatic pressure increases in proportion to depth, so if the water tank is large but shallow, the hydrostatic pressure will not be as important, right?
Thanks a lot for those quick and helpful responses! (And thanks for the welcome message Chestermiller!)
That's a good point, I hadn't thought of the speed at which the piston is pushed. For the sake of this situation, we can say it is pushed slowly.
Voko, thanks a lot for your additions. That...
Hello! I just found this website and it looks amazing! I'm not a scientist or anything, but I love it (should've studied physics but oh well), so I think it will be fun and useful for me to join this forum.
I am trying to solve a situation, where I'd like to know how much energy would be...