i chose it because i know that metals + non-metals are ionic... and because they were both non-metals, it made me feel that way. also, i knew that ionic compounds were metal + polyatomic (and that wasn't that, either).
that was my assumption. i just like to make sure i didn't miss something, as...
Thanks for the help so far, Geoff. I am only supposed to list two equivalent (I assume that might be the key word there) resonance forms.
it's from first year university chemistry - just very out of my element.
... O
...//
O - C
...\
... O - H
...O
.../
O - C
...\\
...O -H...
Hi Geoff
I explained my reasoning in the message above you. I thought that the highest lattice and shortest bonds correspond, and I know that as you move up and to the right that they are at the strongest - therefore because F is the farthest and Na is higher than K, I chose NaF.
For the...
I did, sorry. I just didn't type it all. I read through the trends, and just want to make sure I interpreted them correctly. I was under the impression tha the shorter bonds and highest lattice energy would be the same, because the increased lattice = stronger bonds, and the strong bonds are a...
hi Steve, thanks.
I re-checked my answer and realize I think I read the question wrong... Two lone pairs, meaning four all together (I was interpreting it like two, not two pairs) if that makes sense. Then I think it's XeF4.
I have to figure out which has two lone pairs on the central atom between PCl3, ICl4^+, CH3I, XeF4, PCl6^-.
Is it PCl3? I think I did it right but I am not sure.
Thank you.
Are two equivalent resonance forms HCO3^- like this?
... O
...//
O - C
...\
... O - H
...O - H
.../
O - C
...\\
...O
Both structures have brackets and a -.
Also, each O on the left has six dots, the O on the double bond has four, and the O on the H has four as well...
I am not positive if I did this correctly, but I was wondering if someone could check and then, potentially, offer ideas.
The question asked to use bond energies and estimate the energy change deltaH (in kJ/mol) for
N=N + 2H2 --> H2N-NH2
(that first N=N is triple)
I think I just...
Thank you for your help with this.
So I divided 2.9979x10^8 m/s by 5.76 x 10^-7 m
to get nu= 5.20 x 10 ^14 s^-1
Then for the second part (what is the energy in J of one photon of the raditon, I would still multiply 5.20 x 10 ^14 s^-1 by 6.6256 x 10 ^-34 J.sec, and then I would get 3.45 x...