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lohboys
Recent content by lohboys
Engineering
Derivation of Thermodynamic Relations
dG= -SdT + VdP ... now dividing by dV holding temperature constant (dG/dV)T = -S (dT/dV)T + V (dP/dV)T ... now dT and constant temperature cancel out final answer: (dG/dV)T = V (dP/dV)T
lohboys
Thread
Oct 19, 2019
Tags
Derivation
Relations
Thermodynamic
Replies: 1
Forum:
Engineering and Comp Sci Homework Help
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