Recent content by LionelHutz

V = \frac{1}{4\pi\epsilon_{0}}∫^{2\pi}_{0}d\phi∫^{\pi}_{0}sin\thetad\theta∫^{R}_{0} \frac{ρ_{0}r^{2}}{r} r^{2}dr Solving this: V= \frac{ρ_{0}R^{4}}{4\epsilon_{0}} I'm quite happy with this answer, but if it is incorrect please let me know. Thanks for the help

Is V = ρ0R4 / 4ε0 the answer to this problem?

So would the integral from 0 to R work if d\tau = r2sinθdrdd\phi ?

Yes I'm unsure of what my limits are in this case and what d\tau is equal to

Homework Statement Solid ball of charge with radius R and volume charge density ρ(r) = ρ0r2, centred at the origin. I have already found the electric field for r<R and r>R and also the potential at the origin by using the formula: V = -∫E.dl Now i want to find the potential at the...