Recent content by leprofece

2T = 3t 2(60) = 3t so t = 40 seg Ok and now: 3 (40) = 120 m ithink i am ruight now do I?

sure 5T -3T = t 2 T = t t = 2 *60 = 120 please I am not Sure cooecte me if I am not correct and thanks for you reply greetings and regards

John runs at 5 m/s joe runs at 3m/seg the distance to run is 300 m Antony in order to do the race more exciting allows john start t seconds after joe What is the t value so that the race finishes in a tie?? what distance was allowed to joe?? Answer 40 seg and 120 m I don't know how to denote...

A man is standing on the platform of a truck moving at 36 km/hr, in what angle and in what direction the man should the man stand to avoid falling if, in 2 seconds the speed of the truck changes to: (a) 9 km/hr? (b) 45 km/hr ?

How many Coulombs of charge positive and negative are there is a coin of 5 g of mass? Answe: 2,3.105 C I don't know but I have no idea I think there is no enough data

Hello friends Find the matriz A ij) if we know that is a matriz 3x2 a) -(i+j) log bass16 (2) )^{i+j}/(2j + log 10000) If I am asked what is my work?? I said I have no idea of course is matrix before the student studies sum ret and matrix products (

Hello friends(a( Find the matriz A ij) if we know that a) aij = (cubic root (2) )^{i} + {-4}^{j})\{\sqrt{3}} (

\partial \nabla Here you are my free body diagram as you see we disagree in x axe because you have f cos53 - fr The book says that fr must be in the vertical accordin to book in the horizontal there is only one force f cos53

I got 0 and - infnity

calculating limit as x tends to 0 it doesnot exist but in \infty tends to -\infty equating to 0 i got x = 2 /cubic root of 3 is that I have to do?

Yeah I want the drawing or the plot of the free body diagram of the problem That is I required or asked

¿domain and asinptotestotes of x^2y+xy^2 = 2? Answer (inf -2]U(0, inf +) asinptotes AV x = 0 AH y = 0 Oblique x-y = 0 I can isolate y or i mean solving for y

SOLVE THIS PROBLEM And this is the figure I need the free body diagram because the book solve this problem in this way the force normsl is n = fcosx the verticall componente is fsenx = w + miuN why does the fr is vertical in this case?

Ok let's see this integral is too long according to wolphramalpha maybe as prove it did it, it is easier thanks anyway

well after the mistake I got these lnx+xlnx ... is the integral answer