is there an easier way to calculate the dipole moment? I described ## \vec r## in spherical coordinates. I thought at first that due to the symmetry I can assume that dipole-moment only points in the ##z##-direction, but the charge distribution is inhomogeneous, so I made the following...
In the headline to the question the statement should have been:
rotation of macroscopic magnetization = averege (Magnetization current density )
The Magnetization current densities ##\vec{j}_{\text{mag}}^{(i)}## of individual particles ##i## are stationary ##(\vec{\nabla} \cdot...
Ahhhh, ##\vec e_\phi## is zero becaues it is perpendicular to the ##z##- axis., so it will not contribute to a ##z## component.
So I'm now at this point:
$$ \left(\begin{array}{l}0 \\ 0 \\ 1\end{array}\right)=\lambda\left(\begin{array}{c}\sin \theta \cos \phi \\ \sin \theta \sin \phi \\ \cos...
##(\vec {e}_{r'} \times \vec {e}_{\phi})_z=(-\vec {e}_{\theta})_z=\sin \theta ##? I don't know how I can represent ##\vec e_z## in spherical coordinates?
But ##\vec {e}_{r'} \times \vec {e}_{\phi} = \vec {e}_{\theta}## is correct?
True!
First I need to calculate ##\vec{j}(\vec{r}, t)=\rho(\vec{r}, t) \vec{v}(\vec{r}, t)##
Failed attempt:
I tried to use spherical coordinates. Because of the radial symmetrie the magnetic moment will only be...
I'm really sry for that, I meant the heaviside-function and should have wrote ##\vartheta## for the spherical coordinates. I will give you a new calculation in a few minutes
Ich wäre Ihnen sehr dankbar, wenn Sie sich meine Lösung der folgenden Übung ansehen:
A sphere with radius ##R ## is spatially homogeneously loaded and rotates with constant angular velocity ##\vec{ \omega}## around the ##z ## axis running through the center of the sphere.
Calculate the...
The following is an example from my script. I always have trouble identifying useful symmetries. Can someone explain to me why (for example) the vector potential doesn't have a ##z## dependence? I understand that there is no ##\varphi## dependency.
I don't understand why the field of ##\vec{A}##...
Thank you ! :)
It is an exercise to solve for the upcoming exams:
-segment 1 and 2 produce the same magnetic field at a point on the z axis
- a whole circle on the central x-axis would create a magnetic field that points only in the z-direction because of the radial symmetry
- a semicircle...
For the following conductor loop, determine the magnetic field along the ##z##-axis, which passes through the center of the conductor loop and is perpendicular to it.
The conductor loop consists of an infinitely long wire through which a constant current ##I## runs.
Is it possible to determine...