Recent content by LandOfStandar

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    Carnot engine working in reverse poblem-

    the answer is 440Watt and I can not get it either way
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    Carnot engine working in reverse poblem-

    what is the coefficient of performance is 3.8
  3. L

    Carnot engine working in reverse poblem-

    Please someone help I need to understand this the exam is coming up and I need an understand of this
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    Solve Carnot Engine: Efficiency (T1-T3)/T1

    thank you that makes since I now understand the question
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    Carnot engine working in reverse poblem-

    \kappa_1 is that the pump's coefficient of performance with one being the given 3.8 and finding the other as 9.926 are one of the Q 7.54x10^6J what is the other, or is that Q total? k total = 3.8 + 9.9 = 13.7 Q total = 7.54x10^6J what am I trying to get? rate must work be done W net /...
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    Carnot engine working in reverse poblem-

    I did not have those formulas I wish I could find these in my textbook Fundamentals of Physics by Halliday and Resnick ok, thank you
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    Solve Carnot Engine: Efficiency (T1-T3)/T1

    (T1 -T2 + T2 - T3) / (T1 + T2) = (T1 - T3) / (T1 + T2) the problem is the T2 on the bottom
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    Solve Carnot Engine: Efficiency (T1-T3)/T1

    E1 = W1/Qh1 = (Qh1-Ql1)/Qh1 = (T1 - T2)/T1 what do you mean? E2 = W2/Qh2 = (Qh2-Ql2)/Qh2 = (T2 - T3)/T2
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    Carnot engine working in reverse poblem-

    k =Qin/W = Qin/(Qin - Qout) = Tin/(Tin - Tout) the other one was from my text
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    Carnot engine working in reverse poblem-

    Homework Statement A heat pump is used to heat a building. The outside temp is -5.0 Celsius and the temp inside the building is to be maintained at 22 Celsius. The pump's coefficient of performance is 3.8, and the heat pump delivers 7.54MJ as heat to the building each hour. If the heat pump...
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    Solve Carnot Engine: Efficiency (T1-T3)/T1

    [SOLVED] Carnot engine - please help asp I just typed a whole question and as I typed it I solved it, lol! Homework Statement In the 1st stage of a 2-stage Carnot engine, energy is absorbed as heat Q1 at temp T1, work W1 is done, and energy is expelled as heat Q2 at lower temp T2. The...
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    Frequency in two different wires

    I am lost with what was previously said can anyone help
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    Frequency in two different wires

    I don't know which end is attached to the source, what do I do with the nodes because part b ask for them?
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    Frequency in two different wires

    I don't know the frequency or wavelength v= (F/(linear density))^(.5) v= ([10.0 x 9.8]/[2.60 x 1.00 x 10^-2])^(.5) = 61.4 v= ([10.0 x 9.8]/[7.80 x 1.00 x 10^-2])^(.5) = 35.4 I can get that but then I am lost
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