Ok, fair enough. But the answer guide said you could arrive at the following equation for f and I want to know how they got it:
f=\frac{\frac{r}{R}-\frac{I}{mR^2}}{1+\frac{I}{mR^2}}
Homework Statement
I have two equations with two unknowns. I know m, F, R, r and I. I need to find a and f.
m = 2
F = 28
R = 0.25
I = 0.0625
r = 0.1875
I know the ultimate answers are a = 16\frac{1}{3} and f = 4\frac{2}{3}
Homework Equations
(1) Fr-fR=I\frac{a}{R}
(2)...
So here is the source of my question. This is the solution to the physics problem posted by my physics professor at MIT. I probably just posed the question incorrectly, but since what I was really interested in was just "what is the derivative of (1-cos(theta))" I understand now what the answer is.
Homework Statement
In reviewing my last physics exam I found the following statement in the posted solution:
...the derivative of \sqrt{\frac{3g}{l}(1-cos\theta)} is \frac{3g}{2l}sin\theta
Homework Equations
N/A
The Attempt at a Solution
This is from a physics course and I'm...
Homework Statement
Solve this system of equations for x and y.
v=x+y
v^2=x^2+y^2
Homework Equations
The quadratic formula:
x = (-b +/- sqrt(b^2-4*a*c))/(2*a)
The Attempt at a Solution
A TA gave the following advice:
"Make y the subject of the first equation.
Find y2 in terms of v and x...