I'm modeling a moving cart, and I'm trying to determine if the coefficient of kinetic friction changes as a function of speed. Does anyone know of any literature where this is discussed, or if this happens? I would've thought friction solely depends on the types of materials used.
Hi, I'm wondering if anyone has any sources for off-axis point calculation for multiple current carrying loops that contain a soft iron core.
I have been using this resource so far and I can figure out how to include multiple loops. How would I approach these calculations with an iron core...
Ill go through my thoughts again for each answer:
1. I do not believe that at point A the E of the ball is 0. (Location A is inside the sphere) This is because in an insulator even though the charge on the outside is uniformly distributed, the A is not in the center.
2. That is correct...
Homework Statement
A hollow ball of radius 5 cm, made of very thin glass, is rubbed all over with a silk cloth and acquires a negative charge of -9.5e-08 C which is uniformly distributed all over its surface. Location A, shown in the diagram, is inside the sphere, 1 cm from the surface...
Homework Statement
http://imageshack.us/photo/my-images/403/haiss.jpg/
picture
A strip of invisible tape 0.12 m long by 0.014 m wide is charged uniformly with a total net charge of 3 nC (nano = 1e-9) and is suspended horizontally, so it lies along the x axis, with its center at the...
Homework Statement
This is my own question. I am trying to understand what
f'(c)*(b-a) exactly means. I know its (deltaY/deltaX)*deltaX, which gives us deltaY, but does that mean its the net change in Y over the entire interval, or just at point c?
thank you man, i was doing the IW for the rotation for the disk,
and the equation i had with the r perpendicular and momentum included direction because of the right hand rule of the ball i think
the disk is spinning clockwise so its in the -z,
and the right hand rule states that the balls momenta is in the +z?
So i have
((mr^2)/2)w + Rperpendicular(Mass*Velocity)w
=
((3.6kg)*(.7m)^2)/2 * <0,0,-.34> + (0.42m)(0.4kg*-6m/s)*<0,0,1>