The first part of the problem seems easy enough, the free electrons in the wire would move in a circle owing to an electric field that would be induced in the rod which would provide the centripetal force for the same (Please correct me if I am wrong). So we have $$eE=mω^2x$$, where e is the...
Here's a perspective on it: consider a hollow cylinder with a current flowing along its length, now consider a small element on this cylinder. It's easy to see that it would experience a force due to the other elements on the same wire. I like to think of this as a small element (which is...
Can't we use basic centrifugal force for this? My professor told me to think along these lines (we haven't done torque yet) and I just believe that I over complicated my explanation a bit, and that a centrifugal force is pushing the car outside.
Homework Statement
Why do the left wheels of a car rise when it takes a sharp left turn (that is it lurches towards the right)?
Homework Equations
$$a_c= V^2/R$$The Attempt at a Solution
I started by imagining the car as being a part of a very large ring, dx.
Since it's taking a left turn...
This problem is fairly objective (though quite stupid)
What does î(o) represent?
Does it refer to a vector making angle 0 degrees with the x axis?
I searched but couldn't find the answer anywhere. Please help.
Moderator note: post edited and moved from hoemwork
Yes...that was what I wanted to know, because I had thought it would be a spiral but I didn't know the shape of it.Then I came across the logarithmic spiral, and it was the nearest shape that had come close to how I visualized the path. It was an intuitive guess, even though the parameters were...
And is there another equation that can give me the desired information apart from this differential equation, or do I have to depend only on the problem statement for the same?
The spiral I had mentioned was referring to a logarithmic spiral initially, before it attains a circular shape. More appropriately, it was a logarithmic spiral which terminated into a circle, because the radial component will keep on decreasing, and eventually it will become 0 otherwise in the...
That was not what I meant. By path, I meant the trajectory it adopts before it has attained the desired radius. After that, I had taken it for granted that the particles move in concentric circles ( in my book, there was a hint given which said that). So, you mean that it can either keep on...