Recent content by Karl86

  1. K

    How to calculate this dispersion relation

    There is one extra ##\omega## factor in both but I can no longer edit the post. It all worked out anyway, except that I thought there was a general strategy to obtain dispersion relations for generic waves, instead it looks like there are ad hoc methods, so to speak.
  2. K

    How to calculate this dispersion relation

    I have no idea how this dispersion relation was deduced, and also what's the meaning of including plus and minus in the formula.
  3. K

    Energy density due to infinite uniform line charges

    Oh, ok I asked my instructor and I was told to set the reference point not at infinity but at a finite distance from the wire. Do you think that can help?
  4. K

    Energy density due to infinite uniform line charges

    It was not a deliberate sandbag, it is meant to be answered correctly, so as things stand I am failing to answer it properly, and yet I communicated it to you correctly, and I am persuaded the discussion is correct.
  5. K

    Energy density due to infinite uniform line charges

    Yes, I'm convinced. The discussion that arose from a seemingly innocent problem was remarkable though :D
  6. K

    Energy density due to infinite uniform line charges

    The field is constant and pushes it away from the wire, the charge never stops, so the KE is never 0. IS that right?
  7. K

    Energy density due to infinite uniform line charges

    Ok so you stand by your analysis that it seems not well defined, but what did you mean when you said that ##C\log(|r_2-r_1|)## can be deduced from the configuration? How?
  8. K

    Energy density due to infinite uniform line charges

    You are seeing it in terms of energy to get a certain configuration, but the wires are fixed in a constant position. There are no assumptions on how close or far they are, not infinitely far though, one intersects the xy plane in a point r_1 and the other in a point r_2. What the question seems...
  9. K

    Energy density due to infinite uniform line charges

    The answer is given: it is ##-\frac{2\lambda^2}{4\pi\epsilon_0} \log(|r_2-r_1|)##. What I am asked is to prove that it can be written like that. How is it you got that expression naively? If I get right the ##\log(|r_2-r_1|)## bit I am basically done.
  10. K

    Energy density due to infinite uniform line charges

    It was simply suggested in class I have literally 0 reference on it. And the energy density was defined as the energy in the field between the plane z=a and z=a+1. But I cannot find a way to calculate that that doesn't end up being infinite.
  11. K

    Energy density due to infinite uniform line charges

    Those integrals were infinite too :(
  12. K

    Energy density due to infinite uniform line charges

    But that gives something like ##C\cdot \log\frac{a + \sqrt{x^2+a^2}}{-a+\sqrt{x^2+a^2}}## assuming a symmetric rod, times some constant, ##1/2 \lambda## and that limit is still infinite for ##a \rightarrow \infty##...
  13. K

    Energy density due to infinite uniform line charges

    Actually, one last thing. Here I somehow convinced myself I would get ##\log (|r_2-r_1|)## but I actually don't, do I? $$ -\frac{\lambda}{2\pi\epsilon_0}\left(\log\frac{r_1}{a}+\log\frac{r_2}{a}\right) = -\frac{\lambda}{2\pi\epsilon_0}\left(\log(r_2) - \log(r_1) \right)$$ which is quite...
  14. K

    Energy density due to infinite uniform line charges

    Thank, appreciate your help. At this point I am convinced that it's just about getting those differential equations for the generic fields. But I think that this question could also shed light on the matter: if we double the charge density on the rods (##2\lambda## instead of ## \lambda ##) how...
  15. K

    Energy density due to infinite uniform line charges

    Ok, and equation-wise what can one say? Taking the curl of one of Maxwell's equations I get $$ \nabla \times \nabla \times \mathbf{E} = -\frac{\partial}{\partial t} \nabla \times \mathbf{B}$$ from which $$ \nabla(\nabla \cdot \mathbf{E}) - \nabla^2 E = - \mu_0 \frac{\partial \mathbf{J}}{\partial...
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