Recent content by Karim Habashy

I think I made a mistake in the input of the light year value, thanks for the correction. So, can we say that Gauss's law is limited to the charge distributions which are very dense (relative to the distance to the outside point of field application) so as to have a uniform radial electric field...

Ok we can take the argument to the other extreme, We can charge the sphere unifromally with 10^48 electrons to have have about 0.4 electrons /nm2, will the E-field at q be (10^48)*q/4πε*R^2 ?. The point is (I think) we can charge the sphere with any number of point charges and most of the time...

How small is small rotations ?

BvU, I think my scenario is quite simple. I will try to make it simpler to emphasize my point and I will start with a picture: [PLAIN]http:// So what is the Electric field at q? given that the sphere has symmetric charge distripution of ex.14 (I have only drawn in 2D). Is the field 12*q/4πε*R^2...

The argument includes waiting 20+ or more for equilbrium to be established, so that the information about the presence of the 10^55 electrons is comunicated across all space.

@BvU my assumption is something of this sort, or that we can ignore the contributions from the atoms and their electronic clouds. The shell is initially electrically neutral and charging the shell with any charge (Q) will give a charge denisty Q/4πR^2. Also, let's look at the other extreme, we...

Hi All, My question goes as follows: Suppose that, we charge a conducting very thin spherical shell in 'empty space' with a charge equivalent to 16 electrons. The radius (R) of the shell is 20 light years. We wait 20+ years for the electrons to reach equilibrium. Then, we approach one electron...

Hi, Is measuring the temperature dependent conductivity a reliable way of determining the activation energy/ the dopant level of a wide band-gap transition metal oxide. Also does the activation energy in this case change with the dopants density. Thanks.

You are right, thanks. the integration would be ∫(sinx)2 dx which is Pi/2.

Hi All, This is a very elementary question but, from calculus : ∫sinx dx from 0 to pi = 2, but i thought of it, in terms of the attached driagram. And if we think of it, this way, the integration is the area of a half circle of radius one and is equal to Pi/2. Where did i go wrong ?

I apologize, i meant (low energy/Long Wavelength), and thanks for the information.

Hi All, Does a beam of "low energy/small wavelength" gets refracted when passing from one media to another. Thanks

Hi All, Is the Angular momentum conserved at the singularity ? Thanks in advance

Ya, you r right, i got it -_- . My mind played tricks on me, i had the wrong mental image of an inscribed polygon in a circle, haven't done geometry in sometime. Thanks

∠'CBO' = 90 and ∠'OCB' = δ ∴ from the Δ 'OCB' we find that : ∠'COB' = 180-90-δ = 90-δ