Recent content by kahlan

hello welcome i think it is so easy, right we will apply L'Hopital's rule for top and bottom top = 1 - x^t ==> -x^t lnx bottom = t ==> 1 then limit t----->0+ -x^t lnx / 1 t=0 so our limit will be -lnx hi -x^t = -x^0 =1

hello there hi everybody just i have been taken my final exam for calculus one CALCULUS I there was one qeustion which i was confouse while i was reading it Set up the intgeral area of unit circle?

sorry

it sould be like \lim_{x\to\infty}x[(1+ 1/x)^x- e] sorry guys as well as answer will be 1

\lim_{x\to\infty}x[(1+ 1/x)^x- e]

how are u every one there i am happy to be one of ur friends just we have challenge because of this limit so i hope that someone donate to solve it thanx