Okay the only other equation I found that uses distance, acceleration and time is x= vot + .5at^2 and when i solve for vo it still comes out to 4.76. am i missing something?
A locomotive is accelerating at 1.7 m/s2. It passes through a 20.0-m-wide crossing in a time of 2.8 s. After the locomotive leaves the crossing, how much time is required until its speed reaches 33 m/s?
I really don't know how to approach this equation, I feel like it will involve more than...