but before doing that... i should watch the units more carefully next time...
yeah... i will have to charge the yellow car with over speeding... i should really know my units...
so i converted 70 km/hr to m/s
and i get 19.44m/s
and the driver did... get over that limit...
sorry, sometimes...
ok!
So this is what i did...
well first you need to find Fnet so...
its
Ʃfx
Fa-Ff=+ma
since the velocity is constant... i think that acceleration is zero... so i get
75.8-Ff=0
________________________________
and next...
ƩFy
FN-Fw=0
FN=Fw
FN=88.2
and if we apply the...
hahah... tnx! I knew i was right... one way or another.
with that out of the way...
so now i got
m1=2.674 kg
m2=1.100 kg
vi2=0
and with two unknowns...
vi1=?
vf =?
and in order to fine them i got these two equations...
vi1=(m1+m2)vf/m1 and
vf= m1vi1/(m1+m2)
hmm... would i...
thanks for confirming and killing any doubts i have.
for the mu, i used the equation for the spring scale and friction block
µ = Fspring /Fnormal
µ =Fspring /(mblock •g )
so i assumed that the horizontal force is from the spring scale and the vertical force is from the friction...
Homework Statement
please check this link out to make it simpler to understand...
http://www.scribd.com/doc/62694749/MC-Collision1D2
there is a friction block and a spring scale... it gives two measurements (the vertical force and the horizontal force)
Fvertical=88.2 N and
Fhorizontal=75.8 N...