Recent content by jschim

It would be equal to the hanging mass times acceleration, in this case, gravity. f=ma

netF=tension-weight right??

weight acts downwards, and tension acts upwards

I just realized I messed up my units on #3 by a power of 10. It should be .588 rather than .0588 and 470.4 rather than 47.4

I tried part two again based on you advice and I think I did it correctly. Fnet=ma T-mg=mg T=2mg T=2(.4)(9.8) T=7.84 N

here are the last two parts. Thank you for helping me!

I tried my best, but I am not sure how to work around finding tension with the spring involved

here is the free body diagrams, I am working on the rest

sorry, I am not very good at physics, the equilibrium extension is 0.2 meters

the spring at equilibrium is 0.2 meters

1. Draw Free body Diagram for each weight. 2. Solve for Tension in Rope. 3. Find Spring Constant. 4. Find omega (w, or angular velocity)