Initially the hot air balloon is stationary so...
FB=Fg
ρgV=mg
m=1319.2...kg
FB=Fg=12941N
In the air...
a=2d/t^2=0.933...m/s^2
Fnet=FB-Fg
(1319-x)(0.93...)=12941-(1319-x)g
x=114.6 kg
but apparently this is wrong?...
Homework Statement
Write the equations of tangent lines to the curve of the implicit function x2+2x+2y2-4y=5
that are normal to the line y=x+122. The attempt at a solution
I know that the slope has to be m=-1
I found the derivative using implicit differentiation:
dy/dx=(-2x-2)/(4y-4)
Now I am...
So I guess my question is which of these two equations do we use in the tension force equations (if either is correct...and if my tension force equations are correct...):
a2= -asurface + a1
a2= -2a1
So based on the previous post #43 would that mean that
a2= -2a1
If that is the case then it seems as though the acceleration of the surface is not needed as
T2 = m2(a2 +g)
T1 = m1(a1+μg)
Which I would equate the two equations and just for a1
Based on intuition, I don't think we would have...
So if you were to define the right as a negative direction, as indicated in the question would the formulae become:
a2= -asurface + a1 ? Does that seem valid?
I am not ignoring it, I just don't know. As I was taught that the accelerations of both the objects would be the same just in opposite directions, but you have said that is not the case, so I don't know what to assume.