Recent content by JohnSmith236

  1. J

    Using the steady flow energy equation, find the power required

    Oh yes of course, thank you very much Chester I really appreciate the fact that you pointing that out to me I completely left out that equation by mistake.
  2. J

    Using the steady flow energy equation, find the power required

    So therefore, the power would be equal to -W+˙m(hin−hout+gzin−gzout))
  3. J

    Using the steady flow energy equation, find the power required

    Yes, at the bottom of the pipe where the water exits it is static, meaning the change in height is 2m-0m is that right? p1 - p2 = γ (h2 - h1) where γ is the specific weight (N/m3) which is γ = ρ g, γ = 1000*9.81=9810 Not sure if this is the equation i should've used need help on this part of the...
  4. J

    Using the steady flow energy equation, find the power required

    Thank you for your response. Yes, it is static however I am not sure what the formula is for the pressure head (h) and whether the formula I have used is correct since I haven't used the diameter given. Furthermore, how would I introduce the effects of friction into the problem?
  5. J

    Using the steady flow energy equation, find the power required

    Homework Statement A pump is used to move water through a pipe of diameter 150mm, Figure below. The water has a temperature of 20 Celsius and an absolute pressure of 100KPa. The pump moves the water up a vertical distance of 2m and the water exists at atmospheric pressure. Q1) Assuming the...
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