first of all my understanding of scattering is shamefully low so please keep in mind...
σdif. = (z12*z22) / 16Tα2 * 1/ sin4(ϑ/2)
dΩ= 2πsinϑdϑ
σR=∫σdif dϑ σdif = dσ/dΩ and the integral borders are 40° and 41°
now those 105 = ndσr ? where d is the thickness and n = densiti times NA/M
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Homework Statement
Onto an Aluminium 50μm thick plate, we send a beam of alpha particles with unknown kinetic energy. the cross section of the beam is 2cm2, density 1013 / scm2 . Whats the kinetic energy of the particles if every second we sense 105 scattered particles between the angles 40°...