Hmmmm
0.015 is pressure at sea level...
so 0.015 should be P(0)
Is it that I'm simply misunderstanding the question and I should assume that temperature of 15C is constant? But how would I find pressure at the height the particle is at? And if I'm not assuming the temperature is constant...
A. Given that the average diameter of all particles in a sample is 16 nm, te density of all particles is 1.25 x 10^-4 g/cm^3, and the density of the sample of air is 100 microgram/cm^3, how many particles are in 1 L of this air sample?
V(particle) =2.14x10^-18 cm^3
x density = 2.675x10^-22 g
1...
Okay so, this second equation was derived from the first using an 8 km scale height and is true under the conditions of atm pressure units, according to my textbook, that's whereni acquired all of my information, I've attached a photo of the page, maybe you can see what I'm not understanding...
Homework Statement
At an altitude of 50 km, the average atmospheric temperature is 0C. what is the average number of air molecules per cm^3 of air at this atmosphere?
Given formula:
P(sub h) =
P(sub 0) x e^(-Mgh/RT) =
-(Mgh x 10^5)/2.303RT
Assuming P = 1 atm at sea level and h in km...