Homework Statement
An 8-kg sphere A is moving to the left with a velocity of 15 m/s when it strikes the 45° inclined surface of a 10-kg block B which is moving to the right a 5 m/s. The ball strikes the block 1 meter above the ground. The block is supported by rollers and impact is perfectly...
Homework Statement
integral of sqrt(x^2-36)/x)
Homework Equations
sqrt(x^2-a^2) = asec(u)
Pythagorean identity
The Attempt at a Solution
I used trig sub on the x^2-36 and changed that to x=36sec(u) and dx= 36sec(u)tan(u). I simplified the square root in the numerator using...
Hi, I need to write a paper for my statics class on any new form of technology and it's impact on society. Does anyone have any suggestions for a topic? Any suggestions are greatly appreciated. Preferably something I can find articles about. Thanks in advance!
ok, I think I got this if anyone wants to confirm, still not sure about the x greater or equal to 0 and less than or equal to pi/2, but here goes. csc(x)sqrt(sec^2(x)-1) turns into csc(x)sqrt(tan^2(x)+1-1) after the Pythagorean identity, then simplifies to csc(x)tan(x) after you do the square...
Homework Statement
Simplify this expression: csc(x)sqrt(sec^2(x)-1) with 0 less than or equal x less than pi/2.
Homework Equations
The Attempt at a Solution
Not really sure what they want here, but would a good place to start be to square the entire expression to get rid of the...
ok, yeah I need to learn how you guys post on here in math terms instead of the keyboard, sorry for the confusion of 1/csc(x)+cot(x) being read as (1/csc(x))(cot(x)).. and yeah I just got lucky, because I didn't even think to multiply the top and bottom by the denominator. Thanks again! P.S. is...
ok guys, sorry, the inverse of csc(x)+cot(x) is 1/csc(x)+cot(x), and I saw the 1 on top and just thought it meant switch csc(x)+cot(x) to csc(x)-cot(x), making it equal to the other side, proving the identity, isn't that right?
OK! got it now, the -ln makes me take the inverse by raising the power to negative 1, then I put 1/csc(x)+cot(x) then the 1 on top goes away when I switch the sign on the bottom to negative. Awesome! So i didn't need to worry about the absolute value, or figuring out that csc(x)+cot(x) equaled 1...
Trig identity with natural logs and absolute value??
Homework Statement
-ln|csc(x) + cot(x)|= ln|cscx(x)-cot(x)|
Homework Equations
The Attempt at a Solution
I got that csc(x)=1/sin(x) and cot(x)=cos(x)/sin(x), giving me a common denominator, added together I have...