Recent content by JBauer

Ok, I have the cube root sign removed and my current equation is: |x^2 - 9| = 27 although I do not remember how to work out the absolute values from here...

This equation is correct, although the - 3 is not under the radical. Thanks for the help, J.B.

f(x) = third square root of |x^2 - 9| - 3 I need set everything = to 0, but then what? I'm stuck. Thanks, J.B.

The demand function for a product is given by x = D(p) = 1450 - 3p^3, 0<p<7.85 (please note these should both be less-than-or-equal-to signs) (a) Find the number of units sold when the price per unit is $5.75. D(5.75) = 1450 - 3(5.75)^3 = 879.67 Did I set this up correctly? Can...