Recent content by jayayo

wow stupid oversight on my part. Thanks so much!

Hi~ Sorry- pretty stupid of me. I just thought because they purposely added the fact that the electrons also emitted EM waves of the same frequency, maybe this would increase or decrease the value of the magnetic field. What would change due to the fact that the electrons were emitting EM...

I got from here (page 4 bottom), an equation for x (the distance reflected from its original path) http://sun.iwu.edu/~gspaldin/B_deflection_Lab.pdf Is this why? Does Vacc mean velocity?? Thanks anyone for any clarification..!

Homework Statement Electron A is fired horizontally with speed 1.00 Mm/s into a region where a vertical magnetic field exists. Electron B is fired along the same path with speed 2.00 Mm/s. Which electron has a path that curves more sharply? A does. B does. The particles follow the same...

Homework Statement The uniform 45.6 mT magnetic field in the picture below points in the positive z-direction. An electron enters the region of magnetic field with a speed of 5.29E+6 m/s and at an angle of θ = 30.1° above the xy-plane. Find the radius r and the pitch p of the electron's spiral...

Homework Statement The microwaves in a microwave oven are produced in a special tube called a magnetron. The electrons orbit the magnetic field at 2.99GHz, and as they do so they emit 2.99GHz electromagnetic waves. What is the magnetic field strength? Homework Equations ƒ=qβ/(2Pi*m) Thus...

:bugeye: So I just guessed 14.7N*m and it's right! I guess I assumed two different points (like the previous post suggested) and calculated the torques separate from one another when they are actually about one centre of mass, meaning one is on the centre of mass thus 0 torque (right?).

Me neither :/ No one has clarified. It's an online assignment so all I'm given is the question. Apparently, according to the previous thread with the same question, the centre of mass doesn't matter? So I tried coupling the forces but doing so only results in the same torque values of 14.74...

Thanks- that was a great explanation. So in order for the object to rotate, the torques must not be equal (cancel out). However, I've tried finding the angles at various points between the force and the triangle and have gotten 14.74N*m. I can't seem to get a proper torque calculation.

Also, I just re-calculated assuming the forces were in the same direction. I got 2*14.7N*m = 29.5 N*m which is also incorrect?

Hi! It is the exact same picture. But the force directions are in the opposite direction (?), so I took that into consideration when calculating torque. Could you explain why? Sorry

Homework Statement Two 59.9N forces are applied in opposite directions to the 28.3cm long figure shown. If the angle θ = 29.6°, what is the net torque about the center of mass...